x^(2/5)-2x^(1/5)-3=0

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Solution for x^(2/5)-2x^(1/5)-3=0 equation: 


x in (-oo:+oo)

x^(2/5)-(2*x^(1/5))-3 = 0

x^(2/5)-2*x^(1/5)-3 = 0

t_1 = x^(1/5)

1*t_1^2-2*t_1^1-3 = 0

t_1^2-2*t_1-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

t_1 = (16^(1/2)+2)/(1*2) or t_1 = (2-16^(1/2))/(1*2)

t_1 = 3 or t_1 = -1

t_1 = -1

x^(1/5)+1 = 0

1*x^(1/5) = -1 // : 1

x^(1/5) = -1

( -1 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O

t_1 = 3

x^(1/5)-3 = 0

1*x^(1/5) = 3 // : 1

x^(1/5) = 3

x^(1/5) = 3 // ^ 5

x = 243

x = 243

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